Codehs 8.1.5 Manipulating 2d Arrays Jun 2026

for (int i = 0; i < matrix.length; i++) // For each row for (int j = 0; j < matrix[0].length; j++) // For each column in that row System.out.print(matrix[i][j] + " ");

Checking if a specific value exists within the grid and returning its coordinates.

: You can overwrite a value by assigning it a new one, such as grid[r][c] = newValue . Implementation Example Codehs 8.1.5 Manipulating 2d Arrays

By understanding how to traverse and modify individual elements using nested loops, you will be able to complete CodeHS 8.1.5 effectively.

She couldn’t just copy. She had to:

for (int row = 0; row < studentScores.length && !found; row++) for (int col = 0; col < studentScores[row].length && !found; col++) if (studentScores[row][col] == targetScore) found = true;

function print2DArray(arr) for (let i = 0; i < arr.length; i++) let rowString = ""; for (let j = 0; j < arr[i].length; j++) rowString += arr[i][j] + " "; for (int i = 0; i &lt; matrix

// Search: Check if any student has a perfect score (100) public boolean hasPerfectScore() for (int row = 0; row < scores.length; row++) for (int col = 0; col < scores[row].length; col++) if (scores[row][col] == 100) return true;

This function systematically checks each element and stops as soon as it finds a match. This pattern is useful for everything from locating a "Waldo" in a grid to validating user input. She couldn’t just copy

System.out.println("Class Average: " + myClass.calculateClassAverage()); System.out.println("Has Perfect Score: " + myClass.hasPerfectScore());